Q. If nearly $10^{5}$C liberate 1 g equivalent of aluminium, then the amount of aluminium (equivalent weight 9) deposited through electrolysis in 20 min by a current of 50 A will be
A) 0.09 g
B) 0.6 g
C) 5.4 g
D) 10.8 g
Explanation
(c) $m = zI\ t;so\ 9 = z \times 10^{5}\ or\ \ z = 9/10^{5}$ g $C^{- 1}$
$m = zI\ t = \left( 9 \times 10^{5} \right) \times 50 \times (20 \times 60) = 5.4$ g.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.