Q. By using only two resistances coils-singly, in series or in parallel one should be able to obtain resistance of 3,4,12 and 16 ohm. The separate resistance of the coil are
A) 3 and 4
B) 4 and 12
C) 12 and 16
D) 16 and 13
Explanation
(b) If we take $R_{1} = 4\Omega$, $R_{2} = 12\Omega$, then in series resistance
$R = R_{1} + R_{2} = 4 + 12 = 16\Omega$
In parallel, resistance
$R = \frac{4 \times 12}{4 + 12} = 3\Omega$
$So,\ \ \ R_{1}4\Omega\ \ and\ R_{2} = 12\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.