In a thermo-couple, one junction which is at 0$℃$ and the othe at $t℃$ the emf is given by $E = at^{2} - bt^{2}$. The neutral temperature is given by

Question

Dr. Abubacker · Accepted Answer

(b) $\frac{dT}{dt} = \frac{d}{dt}\left( at^{2} - bt^{3} ight) = 2at - 3bt^{2}$
When $t = t_{n}(ie,\ $neutral temperature), $\frac{dE}{dt} = 0$
$	herefore 0 = 2at_{n} - 3bt_{n}^{2}\ \ or\ t_{n} = \frac{2a}{3b}$.

Q. In a thermo-couple, one junction which is at 0$℃$ and the othe at $t℃$ the emf is given by $E = at^{2} - bt^{2}$. The neutral temperature is given by

Explanation

Reviewed by Dr. Abubacker

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