(a) If E is the emf of the battery, r the internal resistance, i the current drawn and V the PD across the plates of battery, then
$V = E - ir$
Case I When the direction of current in the battery is from –ve to +ve or outside +ve to –ve, then
$i = + ve\ \ \ \ \ \ \ \ \ \ \ \ $(during discharging)
V<E
Case II When the direction of current in the battery is form +ve to –ve or outside –ve to +ve, then
$i = - ve$ (during discharging)
$V = E + ir$
$\Longrightarrow$V>E
Case III When zero current, then
$i = o$
$V = E$