Q. To liberate two litres of hydrogen at 222.4 atmosphere from acidulated water the quantity of electricity that must pass through is
A) 44.8 C
B) 96500 C
C) 193000 C
D) 386000 C
Explanation
(d) $V_{2} = \frac{P_{1}V_{1}}{P_{2}} = \frac{22.4 \times 2}{1} = 44.8$ L
11.2 L of $H_{2}$ is liberated by charge $= 96500$ C
44.8 L of$\ H_{2}$ is liberated by charge
$= \frac{96500}{11.2} \times 44.8 = 386000$C
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.