Q. How much work is required to carry a $6\ \mu C$ charge from the negative terminal to the positive terminal of a $9\ V$ battery
A) $54 \times 10^{- 3}J$
B) $54 \times 10^{- 6}J$
C) $54 \times 10^{- 9}J$
D) $54 \times 10^{- 12}J$
Explanation
(b) $W = qV = 6 \times 10^{- 6} \times 9 = 54 \times 10^{- 6}J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.