Q. Two different metals are joined end to end. One end is kept at constant temperature and the other end is heated to a very high temperature. The high depicting the thermo $e$.m.f. is
A)
B)
C)
D)
Explanation
(d) $E = \alpha t + \frac{1}{2}\beta t^{2},$ graph between $E$ and $t$ will be a parabola, such that first emf increases and then decreases
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.