Q. When connected across the terminals of a cell, a voltmeter measures $5V$ and a connected ammeter measures $10\ A$ of current. A resistance of $2\ ohm$ is connected across the terminals of the cell. The current flowing through this resistance will be
A) $2.5\ A$
B) $2.0\ A$
C) $5.0\ A$
D) $7.5\ A$
Explanation
(b) Emf $E = 5V$, Internal resistance $r = \frac{5}{10} = 0.5\Omega$
Current through the resistance $i = \frac{5}{(2 + 0.5)} = 2A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.