Q. The internal resistances of two cells shown are $0.1\ \Omega$ and $0.3\ \Omega.$ If $R = 0.2\Omega,$ the potential difference across the cell

A) $B$ will be zero
B) $A$ will be zero
C) $A$ and $B$ will be $2V$
D) $A$ will be $> 2V$ and $B$ will be $< 2V$
Explanation

(a) Applying Kirchhoff’s law
$(2 + 2) = (0.1 + 0.3 + 0.2)i \Rightarrow i = \frac{20}{3}A$
Hence potential difference across $A$
$= 2 - 0.1 \times \frac{20}{3} = \frac{4}{3}V$ [less than $2V$]
Potential difference across $B = 2 - 0.3 \times \frac{20}{3} = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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