Q. For a thermocouple, the inversion temperature is $600℃$ and the neutral temperature is $320℃.$ Find the temperature of the cold junction?
A) $40℃$
B) $20℃$
C) $80℃$
D) $60℃$
Explanation
(a) Neutral temperature $T_{n} = \frac{T_{c}\ + \ T_{f}}{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 320{^\circ} = \frac{T_{c} + \ 600{^\circ}}{2}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 640{^\circ} = T_{c} + 600{^\circ}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ T_{c} = 40℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.