Q. A moving coil galvanometer has a resistance of $50\Omega$ and gives full scale deflection for $10\ mA.$ How could it be converted into an ammeter with a full scale deflection for $1A$
A) $50/99\ \Omega$ in series
B) $50/99\ \Omega$ in parallel
C) $0.01\ \Omega$ in series
D) $0.01\ \Omega$ in parallel
Explanation
(b) $S = \frac{i_{g} \times G}{i - i_{g}} = \frac{10 \times 10^{- 3} \times 50}{1 - 10^{- 3} \times 10} = \frac{50}{99}\Omega$ in parallel
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.