Q. At steady state, energy stored in capacitor is
A) $4 \times 10^{- 6}$ J
B) 2 J
C) 4 J
D) Zero
Explanation
(a) $V_{A} - V_{B} =$ emf of the cell = 2 V
$\therefore U = \frac{1}{2}CV^{2} = \frac{1}{2} \times 2 \times 10^{- 6} \times (2)^{2} = 4 \times 10^{- 6}$ J
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.