(b) Mass of copper deposited,
$\ m = volume \times density$
$= (area \times thickness) \times density$
$= \lbrack 2 \times (12 \times 3) \times 0.002\rbrack \times 8.9$ g
$\ t = \frac{m}{zI} = \frac{\lbrack 2(12 \times 3) \times 0.002 \times 8.91\rbrack}{33 \times 10^{- 5} \times 5} = 776$s.