Q. When a charged particle of charge $e$ revolves in circular orbit of radius $r$ with frequency $n$, then orbital current will be
A) $\frac{ev}{\pi r^{2}}$
B) $\frac{ev}{4\pi r}$
C) $\frac{ev}{2\pi r}$
D) $\frac{ev}{4\pi r^{2}}$
Explanation
(c) If a charged particle of charge q resolves in a circular orbit of radius r with frequency v, then the orbital current is given by
$I = qv$
$or\ \ \ \ \ I = q\frac{\omega}{2\pi}\ \ \left( \because = 2\pi v \Longrightarrow v = \frac{\omega}{2\pi} \right)$
$I = \frac{ev}{2\pi r}\ \ \ \ \ \ \ \ \ \ \ \ \ \ (\because v = r\omega)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.