Q. The temperature of the cold junction of a thermocouple is $0℃$ and the temperature of the hot junction is $T℃$. The emf is $E = 16T - 0.04T^{2}\ \mu$V. The inversion temperature $T_{i}$ is
A) 200$℃$
B) 400$℃$
C) 100$℃$
D) 300$℃$
Explanation
(b) $E = 16T - 0.04T^{2}$
At temperature of inversion, $E = 0$
$\therefore 16T_{i} - 0.04T_{i}^{2} = 0$
$\Rightarrow T = \frac{16}{0.04} = 400℃$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.