Q. A current of $\left( \frac{2}{3} \right)A$ produces a deflection of 60${^\circ}$ in a tangent galvanometer. The reduction factor is
A) $\left( \frac{2}{3} \right)A$
B) 2A
C) $\left( \frac{2}{3} \right)A$
D) $\left( \frac{2}{\sqrt{3}} \right)A$
Explanation
(c) $K = \frac{I}{\tan\theta} = \frac{2/\sqrt{3\ }}{\tan{60{^\circ}}} = \frac{2}{3}A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.