Q. A series combination of two resistors $1\ \Omega$ each is connected to a $12\ V$ battery of internal resistance $0.4\ \Omega.$ The current flowing through it will be
A) $3.5\ A$
B) $5\ A$
C) $6\ A$
D) $10\ A$
Explanation
(b) $i = \frac{12}{(1 + 1) + 0.4} = 5A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.