Q. In the circuit shown, the point $'B'$ is earthed. The potential at the point $'A'$ is
A) $14\ V$
B) $24\ V$
C) $26\ V$
D) $50\ V$
Explanation
(b) Current in the given circuit $i = \frac{50}{(5 + 7 + 10 + 3)} = 2A$
Potential difference between $A$ and $B,\ V_{A} - V_{B} = 2 \times 12$
$\Rightarrow V_{A} - 0 = 24V \Rightarrow V_{A} = 24\ V$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.