Q.
A current of $3\ amp.$ flows through the $2\Omega$ resistor shown in the circuit. The power dissipated in the $5\Omega$ resistor is
A) $1\ watt$
B) $5\ watt$
C) $4\ watt$
D) $2\ watt$
Explanation
(b) Current flowing through $2\Omega$ resistance is $3A,$ so P.D. across it is $3 \times 2 = 6V$
Current through the bottom line $= \frac{6}{1 + 5} = 1A$
$\therefore$ Power dissipated in $5\Omega$ resistance is
$P = i^{2}R = (1)^{2} \times 5 = 5W$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.