Q. In voltaic air cell if 5g zinc is consumed, how many ampere hours shall we get?
A) 2.05
B) 8.2
C) 4.1
D) $5 \times 5.38 \times 10^{- 3}$
Explanation
(c) $m = zq$
$\Rightarrow q = \frac{m}{z} = \frac{5 \times 10^{- 3}}{3.387 \times 10^{- 7}}$
$q = 1.476 \times 10^{4}$C
Since a current of 1 A for 1 h gives a charge of 3600 C,
$\therefore$ 1 A h = 3600 C
$\Rightarrow q = \frac{1.476 \times 10^{4}}{3600}Ah = 4.1\ Ah$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.