Q. Four resistances carrying a current shown in the circuit diagram re immersed in a box containing ice at 0$℃$. How much ice must be put in the box every 10 min to keep the average quantity of in the box constant?
A) 5 kg
B) 1.19 kg
C) 3 kg
D) 2.29 kg
Explanation
(b) Total resistance between points $P\ and\ Q$,$\ \ \ \ \ \ \ \ \ \ \ \ \ $
If $m$ gram of the ice mean m given time $t$, then As per question,
$(10)^{2} \times \frac{20}{3}(10 \times 60) = m \times 80 \times 4.2$
or $m = \frac{100 \times 20 \times 10 \times 60}{3 \times 80 \times 4.2} = 1.19 \times 10^{3}$ g
= 1.19 kg.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.