(c) Charge flowing in 30 min,
$q =$ area under graph
$= \left\lbrack \frac{0.1 \times 10}{2} + 0.1 \times 10 + \frac{0.1 \times 10}{2} \right\rbrack \times 60$
$\ = 120$C
$\therefore m = zq = \frac{M}{F}q = \frac{31.5}{96500} \times 120 = 0.039$ g