Q. A milliammeter of range $10\ mA$ has a coil of resistance $1\ \Omega.$ To use it as voltmeter of range $10\ volt,$ the resistance that must be connected in series with it, will be
A) $999\ \Omega$
B) $99\ \Omega$
C) $1000\ \Omega$
D) None of these
Explanation
(a) $R = \frac{V}{i_{g}} - G = \frac{10}{10 \times 10^{- 3}} - 1 = 999\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.