Q. Three resistances $4\ \Omega$ each are connected in the form of an equilateral triangle. The effective resistance between two corners is
A) $8\ \Omega$
B) $12\ \Omega$
C) $\frac{3}{8}\Omega$
D) $\frac{8}{3}\Omega$
Explanation
(d) Two resistances in series are connected in parallel with the third. Hence $\frac{1}{R_{p}} = \frac{1}{4} + \frac{1}{8} = \frac{3}{8} \Rightarrow R_{p} = \frac{8}{3}\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.