Q. For a metallic wire, the ratio $\frac{V}{i}\ (V =$applied potential difference and $i$=current flowing ) is

A) Independent of temperature
B) Increases as the temperature rises
C) Decreases as the temperature rises
D) Increases or decreases as temperature rises depending upon the metal
Explanation

(b) The resistance of a metallic wire at temperature $t{^\circ}C$ is given by
$R_{t} = R_{0}(1 + \alpha t)$
Where $\alpha$ is coefficient of expansion.
Hence, resistance of wire increases on increasing the temperature. Also, from Ohm’s law, ratio of $\frac{V}{i}$ is equal to R $ie$,
$\frac{V}{i} = R$
Hence, on increasing the temperature the ratio$\frac{V}{i}$ increases.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.