Q. A cell of $emf\ 6\ V$ and resistance $0.5\ ohm$ is short circuited. The current in the cell is
A) $3\ amp$
B) $12\ amp$
C) $24\ amp$
D) $6\ amp$
Explanation
(b) $i = \frac{E}{r} = \frac{6}{0.5} = 12\ amp$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.