When a current I is passed through a wire of constant resistance, it produces a potential difference $V$ across its ends. The graph drawn between log I and log V will be

Question

Dr. Abubacker · Accepted Answer

(a) According to ohm’s law $V = iR$
$\Rightarrow \log_{e}{V = \log_{e}{i + \log_{e}{R \Rightarrow \log_{e}{i = \log_{e}{V - \log_{e}R}}}}}$
The graph between $\log_{e}I$ and $\log_{e}V$ will be a straight line which cuts $\log_{e}V$ axis and it’s gradient will be positive

Q. When a current I is passed through a wire of constant resistance, it produces a potential difference $V$ across its ends. The graph drawn between log I and log V will be

Explanation

Reviewed by Dr. Abubacker

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