Q. The reading of the ammeter as per figure shown is
A) $\frac{1}{8}A$
B) $\frac{3}{4}A$
C) $\frac{1}{2}A$
D) $2\ A$
Explanation
(b) Resistance across $XY = \frac{2}{3}\Omega$
Total resistance
$= 2 + \frac{2}{3} = \frac{8}{3}\Omega$
Current through ammeter
$= \frac{2}{8/3} = \frac{6}{8} = \frac{3}{4}A$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.