Q. Silver and copper voltameter are connected in parallel with a battery of $e$.m.f. $12\ V.$ In $30\ minutes,\ 1g$ of silver and $1.8g$ of copper are liberated. The power supplied by the battery is $(Z_{Cu} = 6.6 \times 10^{- 4}g/C\ $and$\ Z_{Ag} = 11.2 \times 10^{- 4}g/C)$
A) $24.13\ J/sec$
B) $2.413\ J/sec$
C) $0.2413\ J/sec$
D) $2413\ J/sec$
Explanation
(a) The current taken by the silver voltameter
$I_{1} = \frac{n}{Zt} = \frac{1}{11.2 \times 10^{- 4} \times 30 \times 60} = 0.496\ A$
and by copper voltameter
$I_{2} = \frac{1.8}{6.6 \times 10^{- 4} \times 30 \times 60} = 1.515\ A$
The current$\ I = \left( I_{1} + I_{2} \right) = 2.011\ A$
Power $P = IV = 2.011 \times 12 = 24.132\ J/sec$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.