Q. A thermo-$e$mf $V$ appears across a conductor maintained at a temperature difference $T.$ The thomson coefficient is then given by
A) $- T^{2}\frac{d^{2}V}{dT^{2}}$
B) $T^{2}\frac{dV}{dT}$
C) $- T\frac{d^{2}V}{dT^{2}}$
D) $- \frac{1}{T^{2}}\frac{dV}{dT}$
Explanation
The correct answer is Option C: $- T\frac{d^{2}V}{dT^{2}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.