(b) Let $q$ be the charge flowing through copper voltmeter.
The charge flowing through silver voltmeter $= (2000 - q)$
Now, $m = z_{Cu}q = z_{Ag} \times (2000 - q)$;
$\therefore q = \frac{Z_{Ag}}{Z_{Cu}} \times (2000 - q)$
$= \frac{1.008 \times 10^{- 6}}{3.36 \times 10^{- 7}} \times (2000 - q)$
$\ q = 1500$ C