Q. Three equal resistances, each of 10 $\Omega$ are connected as shown in figure. The maximum power consumed by each resistance is 20 W. What is maximum power that can be consumed by the combination?
A) 5 W
B) 15 W
C) 30 W
D) 60 W
Explanation
(c) Resistance of the combination
$R^{'} = \frac{10 \times 10}{10 + 10} + 10 = 15\Omega$
$\because P = I^{2}R \Rightarrow I \propto R$
$\therefore\frac{P}{P'} = \frac{R}{R'} \Rightarrow P^{'} = \frac{15}{10} \times 20 = 30\Omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.