A wire of resistance 18$\Omega$ is divided into three equal parts. These parts are connected in side of triangle, the equivalent resistance of any two corners of triangle will be

Question

Dr. Abubacker · Accepted Answer

(d) To find equivalent resistance across
BC, AB and AC is in series
$R^{'} = 6 + 6 = 12\Omega$
$12\ \Omega\ and\ 6\Omega\ $is in parallel
Total resistance,
$R = \frac{12 	imes 6}{12 + 6}$
$R = \frac{72}{18} = 4\Omega$

Q. A wire of resistance 18$\Omega$ is divided into three equal parts. These parts are connected in side of triangle, the equivalent resistance of any two corners of triangle will be

Explanation

Reviewed by Dr. Abubacker

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