Q. A current of $2.0\ ampere$ passes through a cell of e.m.f. $1.5\ volt$ having internal resistance of $0.15\ ohm.$ The potential difference measured, in $volt,$ across both the ends of the cell will be
A) 1.35
B) 1.50
C) 1.00
D) 1.20
Explanation
(d) $V = E - ir = 1.5 - 2 \times 0.15 = 1.20\ Volt$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.