(c) Given, $i_{g} = i,\ G = R_{0};$ $i\ \ = n\ i + i = (n + 1)\ \ i$ $\therefore\ S = \ \frac{i_{g}\ G}{i - i_{g}} = \frac{iR_{0}}{(n + 1)i - i} = \frac{R_{0}}{n}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.