Q.
The proton is energy 1 MeV describes a circular path in plane at right angles to a uniform magnetic field of $6.28 \times 10^{- 4}\ T.$ The mass of the proton is $1.7 \times 10^{- 27}\ kg.$ The cyclotron frequency of the proton is very nearly equal to
A) $10^{7}\ Hz$
B) $10^{5}Hz$
C) $10^{6}\ Hz$
D) $10^{4}\ Hz$
Explanation
(d) Cyclotron frequency is given by
$\ \ \ \ v = \frac{qB}{2\pi m}$
$\therefore v = \frac{1.6 \times 10^{- 19} \times 6.28 \times 10^{- 4}}{2 \times 3.14 \times 1.7 \times 10^{- 27}}$
$\ \ \ \ \ \ \ \ = 0.94 \times 10^{4}\ \approx 10^{4}\ Hz$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.