Q. Biot-Savart’s law may be represented in vector form as
A) $\mathbf{dB} = \frac{\mu_{0}}{4\pi}i\frac{\mathbf{dl \times r}}{r^{3}}$
B) $\mathbf{dB} = \frac{\mu_{0}}{4\pi}i\ \mathbf{dl \times r}$
C) $\mathbf{dB} = \frac{\mu_{0}}{4\pi}i\frac{\mathbf{dl \times r}}{r^{2}}$
D) $\mathbf{dB} = \frac{\mu_{0}}{4\pi}i\frac{\mathbf{dl \times r}}{r}$
Explanation
(a) Biot-Savart’s law in vector form is given as
$\mathbf{dB} = \frac{\mu_{0}}{4\pi}i\frac{\mathbf{d1 \times r}}{r^{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.