(c) Magnetic field on the axis of circular current
$B = \frac{\mu_{0}}{4\pi}.\frac{2\pi nir^{2}}{\left( x^{2} + r^{2} \right)^{3/2}} \Rightarrow B \propto \frac{nr^{2}}{\left( x^{2} + r^{2} \right)^{3/2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.