Q. 3A of current is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength 500 gauss and makes an angle of $30{^\circ}$ with direction of the field. It experiences a force of magnitude
A) $3 \times 10^{4}\ N$
B) $3 \times 10^{2}\ N$
C) $3 \times 10^{- 2}\ N$
D) $3 \times 10^{- 4}\ N$
Explanation
(c) Force, $F = Bil\sin\theta$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 500 \times 10^{- 4} \times 3 \times \left( 40 \times 10^{- 2} \right) \times \frac{1}{2} = 3 \times 10^{- 2}\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.