A conducting rod of length $l$ and mass m is moving down a smooth inclined plane of inclination $ heta$ with constant speed $v.$ A vertically upward magnetic field $\overrightarrow{B}\ $exists in space there. The magnitude of magnetic field $\overrightarrow{B}$ is [image:4_image15.emf]

Question

A conducting rod of length $l$ and mass m is moving down a smooth inclined plane of inclination $	heta$ with constant speed $v.$ A vertically upward magnetic field $\overrightarrow{B}\ $exists in space there. The magnitude of magnetic field $\overrightarrow{B}$ is [image:4_image15.emf]

Dr. Abubacker · Accepted Answer

(c) Magnetic force on the rod $F_{m} = Bil.$ It acts in the direction as shown in figure. The rod will move with a constant speed if the net force on the rod is zero. It will be so if
[image:4_image106.emf]
$Bil\cos	heta$ = $mg$sin $	heta$
Or $B = \frac{mg}{il}\frac{\sin	heta}{cos	heta} = \frac{mg}{il}\ tan	heta$

Q. A conducting rod of length $l$ and mass m is moving down a smooth inclined plane of inclination $\theta$ with constant speed $v.$ A vertically upward magnetic field $\overrightarrow{B}\ $exists in space there. The magnitude of magnetic field $\overrightarrow{B}$ is

Explanation

Reviewed by Dr. Abubacker

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