Q. The oscillating frequency of a cyclotron is $10\ MHz$. If the radius of its Dees is $0.5\ m$, then kinetic energy of a proton, which is accelerated by the cyclotron is
A) 10.2 $MeV$
B) 2.55 $MeV$
C) 20.4 $MeV$
D) 5.1 $MeV$
Explanation
(d) $KE = \frac{1}{2}m\left( \frac{Bqr_{0}}{m} \right)^{2}\&\ v = \frac{Bq}{2\pi m}$
$KE = 5.1\ MeV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.