Q. A long solenoid has 800 turns per metre length of solenoid. A current of 1.6 A flows through it. The magnetic induction at the end of the solenoid on its axis is
A) $16 \times 10^{- 4}$ T
B) $8 \times 10^{- 4}$ T
C) $32 \times 10^{- 4}$ T
D) $4 \times 10^{- 4}$ T
Explanation
(b) $B = \ \frac{\mu_{0}ni}{2} = \frac{(4\pi \times 10^{- 7}) \times 800 \times 1.6}{2} = 8 \times 10^{- 4}$ T.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.