If a proton, deuteron and $\alpha$-particle on being accelerated by the same potential difference enters perpendicular to the magnetic field, then the ratio of their kinetic energies is

Question

Dr. Abubacker · Accepted Answer

(d) Kinetic energy in magnetic field remains constant and it is $K = q\ V \Rightarrow K \propto q\ \lbrack V =$ constant]
$	herefore K_{p}:K_{d}:K_{\alpha} = q_{p}:q_{d}:q_{a} = 1:1:2$

Q. If a proton, deuteron and $\alpha$-particle on being accelerated by the same potential difference enters perpendicular to the magnetic field, then the ratio of their kinetic energies is

Explanation

Reviewed by Dr. Abubacker

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