The magnetic field at the centre of a circular coil of radius $r$ carrying current $I$ is $B_{1}$. The field at the centre of another coil of radius $2\ r$ carrying same current $I$ is $B_{2}$. The ratio $\frac{B_{1}}{B_{2}}$ is

Question

Dr. Abubacker · Accepted Answer

(c) $B \propto \frac{1}{r} \Rightarrow \frac{B_{1}}{B_{2}} = \frac{r_{2}}{r_{1}} = \frac{2r}{r} = 2$

Q. The magnetic field at the centre of a circular coil of radius $r$ carrying current $I$ is $B_{1}$. The field at the centre of another coil of radius $2\ r$ carrying same current $I$ is $B_{2}$. The ratio $\frac{B_{1}}{B_{2}}$ is

Explanation

Reviewed by Dr. Abubacker

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