Q. A charge moves in a circle perpendicular to a magnetic field. The time period of revolution is independent of

A) Magnetic field
B) Charge
C) Mass of the particle
D) Velocity of the particle
Explanation

(d) $T = \frac{2\pi m}{qB} \Rightarrow T\ \alpha\ v^{o}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.