Q.
For the arrangement as shown in the figure, the magnetic induction at the centre is
A) $\frac{3\mu_{0}i\pi}{4a}$
B) $\frac{\mu_{0}i}{4\pi a}\ (1 + \pi)$
C) $\frac{\mu_{0}i}{4\pi a}\ $
D) $\frac{3\mu_{0}i}{8al}$
Explanation
(d) $B = \frac{\mu_{0}ia}{4\pi r} = \frac{\mu_{0}}{4\pi a}.\frac{3\pi}{2}\ $
$= \frac{3\mu_{0}i}{8a}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.