Q. Current through ABC and A’ B’ C’ is I. What is the magnetic field at P? $BP = PB^{'} = r$ (Here C’ B’ PBC are collinear)
A) $B = \frac{1}{4\pi}\frac{2I}{r}$
B) $B = \frac{\mu_{0}}{4\pi}\left( \frac{2I}{r} \right)$
C) $B = \frac{\mu_{0}}{4\pi}\left( \frac{I}{r} \right)$
D) Zero
Explanation
(b) Magnetic field $B = 2\left\lbrack \frac{\mu_{0}I}{4\pi r} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.