A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop [image:4_image26.emf]

Question

Dr. Abubacker · Accepted Answer

(b) The magnetic force on $AB\ \ and\ CD$ are equal and opposite due to symmetry and opposite currents in these sides. The magnetic force on $AD.$
[image:4_image113.emf]
$F_{1} = \frac{\mu_{0}i}{2\pi x}\ $ attractive
Magnetic force on $BC$
$F_{2}\  = \frac{\mu_{0}i}{2\pi(x + b)}$ repulsive
Therefore, magnetic force will be experiences towards wire.

Q. A rectangular loop carrying current is placed near a long straight fixed wire carrying strong current such that long sides are parallel to wire. If the current in the nearer long side of loop is parallel to current in the wire. Then the loop

Explanation

Reviewed by Dr. Abubacker

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