Q.
A current $(i)$ carrying circular wire of radius $R$ is placed in a magnetic field $B$ perpendicular to its plane. The tension $T$ along the circumference of wire is
A) $BiR$
B) $2\pi BiR$
C) $\pi BiR$
D) $2BiR$
Explanation
(a) For small element proton
[image:4_image117.emf]
2$T\sin{d\theta}$ = $2R\ d\theta\ iB$
$2Td\theta\ = 2Ribd\theta$
$T\ = iRB$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.