(a) $B_{1} = B_{2} = B = \frac{\mu_{0}}{4\pi} \times \frac{2\pi i}{r}$ $B_{net} = \sqrt{2}B$ $\Rightarrow \frac{B}{B_{net}} = \frac{1}{\sqrt{2}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.